Tuesday 13 September 2011

Chapter 3.5 : Making Connections With Rational Functions and Equations
a) f(x) = (x^2 - x - 6) / (x+2)

  • Restriction : x+2 ≠ 0
                                          x≠ -2

                    Reason : (x^2 - x - 6) / (x+2) = [(x-3)(x+2)] / (x+2)
                                                          So, [(x-3)(x+2)] / (x+2)
                                                                  x-3 = 0 
                                                                      x= 3
  • f(-2) = undefined
  • Graph : 

The graph is discontinuous at x= -2 , while the point is (-2 , -5)


* N = numerator , D = denominator , HA = Horizontal asymptote , LC = Leading coefficient
Remember : N< D is HA  = 0
                   N> D has no HA 
                   N = D is,  HA = y = LC of N / LC of D


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